<PRE><B>Question 1044493</B>
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|----------------------------40
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|---------------------------31 deg
|---------------------------59 deg
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From the angle of depression, it is 20 m to the ground, adjacent.  We are assuming the lower part of the building is 20 m tall.  Using that, the distance directly to the building is tan 31=20/x, where x is adjacent side and the distance to the building.  The angle of depression is the part of the triangle we need here. x=20/tan 31=33.29 m.
Using that distance, the tangent of 40 degrees is opposite over adjacent, and adjacent is 33.29 m
tan 40=x/33.29
33.29*tan 40=x
x=27.93 m.
The height of the building is 47.93 m, 
48 m.

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