Question 1044465
Fits with poisson distribution where it is discrete, proportional to time, random, and could theoretically be infinite although unlikely.
The poisson parameter is 6.
p(0)=e^(-6)6^0/0!
That is e^(-6)=0.0025
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no more than 2 is 0,1,2
p(1)=e^(-6)*6/1!=0.0149
p(2)=e^(-6)*6^2/2!=18*e^(-6)=0.0446
The sum of those 3 is 0.0620
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At least 3 is 1-the above probability, since that is the complement.  It will be 0.9380.
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At a given half day lambda=3
p(0)=e^(-3)=0.0498
Mean and variance are the same, and they are both the parameter lambda, here 6 orders for the mean and sqrt (6) or about 2.45 orders for sd.