Question 1044481
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If they are 270 miles apart after 3 hours, then they are getting further apart at a rate of 90 miles per hour.  Since they are travelling in opposite directions, their individual speeds add to obtain the relative speed between them.  If *[tex \Large x] is the speed of the faster car, and the other car is going 20 miles per hour slower, then the speed of the slower car has to be *[tex \Large x\ -\ 20], and their combined speed must be *[tex \Large 2x\ -\ 20].  Solve


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ -\ 20\ =\ 90]


for *[tex \Large x] then calculate *[tex \Large x\ -\ 20]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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