Question 1044245
The base b of a triangle is c dm longer than the altitude h, and its area is A dm^2. Find the lengths of the base and the altitude.


{{{system(b=h+c,(1/2)bh=A)}}}


{{{(1/2)(h+c)h=A}}}

{{{h^2+ch=A}}}

{{{h^2+ch-A=0}}}

{{{h=(-c+- sqrt(c^2-4*(-A))/2)}}}

{{{highlight(h=(-c+sqrt(c^2+4A))/2)}}}



{{{b=h+c}}}
{{{b=(-c+sqrt(c^2+4A))/2+c}}}
{{{b=-c/2+sqrt(c^2+4A)/2+2c/2}}}
{{{highlight(b=(c+sqrt(c^2+4A))/2)}}}