Question 1044376
Do you mean "ln 4?" as in the natural logarithm of 4? You typed In(4).


To find average value, compute the integral of F(x) dx over the interval, and divide by the length of the interval. That is, you want


*[tex \large \frac{1}{\ln 4} \int_{0}^{\ln 4} e^{2x} - e^x \, dx]


This is equal to *[tex \large \frac{1}{\ln 4} \cdot (\frac{1}{2}e^{2x} - e^x) |^{\ln 4}_{0}]


You should be able to work out the rest.