Question 1044153
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The triangle ABC is right angled at A, AD is drawn perpendicular to BC. AB=8 cm, AC= 6 cm and BD= x cm. calculate x. 
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|BD| = {{{abs(AB)^2/sqrt(abs(AB)^2+abs(AC)^2)}}} = {{{8^2/sqrt(8^2+6^2)}}} = {{{64/10}}} = 6.4 cm.


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&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/geometry/Altitude-drawn-to-the-hypotenuse-in-a-right-triangle.lesson>Altitude drawn to the hypotenuse of a right triangle</A>

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