Question 90888
6
over
3x-2
plus
3
over
2x

-----------------
6/(3x-2)] + [3/2x]
The lcd = (2x)(3x-2)
-------------------------
Write each term with the lcd as its denominator:
[6(2x)/lcd + 3(3x-2)/lcd
Since the denominators are the same combine the numerators to get:
[12x + 9x-6]/lcd
(21x-6]/[2x(3x-2)]
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Cheers,
Stan H.