Question 1043469
year                  price
2008                    26000
2009                    23800
2010                    21600
2011                    1940
2012                    17200
2013                    15000
2014                    12800  
2015                    10600
a.
in 2008,it is new so t=0

{{{slope}}}={{{(-11000/(5))}}}
={{{-(2200)}}} dollars per year

v(t)=-2200t +26000 when t=0 that is 2008,then value of the car is 26000
v(t=0)=-2200*0+26000=26000
b.
in 2015,t=7
v(t=7)=10,600

c.no