Question 1044109
x^2+y^2=r^2
81+25=106 with point 1 and point 2.r=10.3
x^2+y^2=106 is the equation of the circle
The chord"s midpoint is the midpoint of each x and each y, or (7,-2)
The equation of the line that makes the chord has slope (-9-5)/(5-9)=-14/-4=7/2
the point slope formula is y+9=(7/2)(x-5), or y=(7/2)x-53/2.
The perpendicular bisector must have- slope -2/7, the negative reciprocal.
It's equation is y+2=(-2/7)(x-7), or y=(-2/7)x, and this goes through (0,0)
{{{graph(300,300,-20,20,-20,20,sqrt(106-x^2),-sqrt(106-x^2),(7x/2)-(53/2),(-2x/7))}}}