<PRE><B>Question 1044135</B>
let a = the 1st number
let b = the 2nd number
:
Write an equation fore each statement
:
The difference between the first number and two times the second
number is -54,
a - 2b = -54
:
while the sum of three times the first number plus twice the second is 94.
3a + 2b = 94
:
use elimination on these two equation
 a - 2b = -54
3a + 2b = 94
--------------Addition eliminates b, find a
4a = +40
a = 40/4
a = 10
:
Use the 1st equation to find b
10 - 2b = -54
-2b = -54 - 10
-2b = -64
b = -64/-2
b = +32
:
;
Check solutions in the 2nd equation
3(10) + 2(32) = 94
30 + 64 = 94



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