Question 1044129
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I'm assuming you meant to write this equation {{{7^(-x) = 1/4}}}. If so, then,



{{{7^(-x) = 1/4}}}



{{{1/(7^x) = 1/4}}} Rewrite with positive exponents



{{{7^x = 4}}} Flip both fractions (ie take the reciprocals)



{{{(7^x)^2 = (4)^2}}} Square both sides



{{{7^(x*2) = 16}}}



{{{7^(2*x) = 16}}}



{{{(7^2)^x = 16}}}



{{{49^x = 16}}}



The final answer is 16



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