<PRE><B>Question 1044100</B>
let a = the 10&#39;s digit
let b = the units
then
10a+b = the number
:
Write an equation for each statement
:
A two digit counting number has a value that is 7 more than 6 times the sum of its digits.
10a + b = 6(a+b) + 7
10a + b = 6a + 6b + 7
10a - 6a = 6b - b + 7
4a = 5b + 7
:
 If the units digit is 3 less than the tens digit,
b = a - 3
:
Replace b in the 1st equation
4a = 5(a-3) + 7
4a = 5a - 15 + 7
4a - 5a = -8
-a = -8
a = 8
find b
b = 8 - 3
b = 5
:
 what is the number?  85 is the number
:
:
Check this in the first statement simplified equation
4(8) = 5(5) - 7
32 = 25 - 7</PRE>