Question 1044099
Let d be dimes, n be nickels, q be quarters. Then
d+n+q=38
d=2n, so 3n+q=38
.05n+.1(2n)+.25q=4
.25n+.25q=4
3n+q=38
n+q=16
2n=22
n=11
d=22
q=5
There are 11 nickels, 22 dimes, and 5 quarters, totaling $4.00 . ☺☺☺☺