Question 1044017
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There are 2 slots that have a "6" or a "29" on them. The other 36 slots have different numbers. 


The probability of landing on "6" or "29" is 2/38 = 1/19


Multiply this probability by the number of trials to get 266*(1/19) = 14


So we expect the ball will land on 6 or 29 about <font color=red>14 times</font>
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