Question 1043957
.
Amacha leaves her office at 8:00 am and drives to
a client's office at an average rate of 80kph. She
spends 2 hours in meeting,takes a 1 hour lunch
and returns to her own office,driving at an average
of 60kph.If she arrives back at her office at 3:00 pm,
how far apart are the two offices?
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<pre>
Amacha spent driving 7 hours - 3 hours = 4 hours.

Led D be the distance between the offices.

Then you have this equation for the unknown D

{{{D/80 + D/60}}} = 4,   (1)

where 4 = 4 hours is the total driving time.

To solve (1), multiply both sides by the Least Common Denominator 240. You will have

3D + 4D = 4*240,   or   7D = 960.

Hence, D = {{{960/7}}} = 137.14 miles.
</pre>

Solved.