Question 1043602
We are given a rectangle (ABCD) whose interior angles are 90 degrees
:
Diagonal DB bisects angle ADC, also DB is a traversal which implies that angle DBA equals angle ADC = 45 degrees and angle ABE = 135 degrees
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Law of cosines gives us the following
:
AE^2 = 8^2 + 5^2 - (8*5*cos(135)
:
AE^2 = 64 + 25 - (40*cos(135))
:
AE^2 = 89 - (-28.28)
:
AE^2 = 117.28
:
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AE = 10.82
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