<PRE><B>Question 1043847</B>
on a monday afternoon practice, two cyclists took the same amount of time to ride 39 miles and 30 miles, respectively. if a cyclist rode 3 mph faster than the other, what is the rate of each rider? 
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Assuming the faster rider went the further distance,
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Faster rider DATA:
rate = x+3 mph ; distance = 39 miles ; time = d/r = 39/(x+3) hrs
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Slower rider DATA:
rate = x mph ; distance = 30 miles ; time = d/r = 30/x hrs
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Equation:
time = time
30/x = 39/(x+3)
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30x + 90 = 39x
9x = 90
x = 10 mph (slower rider rate)
x+3 = 13 mph (faster rider rate)
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Cheers,
Stan H.
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