Question 90793


    Three times the measure of a complement of a certain angle is equal to 30 more than the measure of the supplement of that angle. Find the measure of each angle.

      Let the angle be = x

     its complement    = 90-x

     its supplement    = 180-x

     three times the complement = 30 more than its supplement

                     3(90-x) = 30+(180-x)

                     270 - 3x = 30+180-x

                     270-180-30 = 3x-x

                        270-210 = 2x

                            60 = 2x

                             x = 60/2 = 30

     The required two angles are  1)90-x = 90-30 = 60

                                 2)180-x = 180-30 = 150