Question 1043776
You would certainly have trouble with the first question if you do not understand the second question.


{{{x=log((0.001))}}}, for base 10;
{{{x=log(10,0.001)}}}
{{{x=log(10,10^(-3))}}}
{{{x=-3*log(10,10)}}}
{{{x=-3*1}}}
{{{highlight(x=-3)}}}



{{{4^(x-1)=8}}}
HINT:  Use base 2.