Question 1043739
if you have 16 milliliters of a 24% glucose solution, how much of a 50% glucose solution must be added to this solution to get a final mixture with a glucose concentration of 35%? 
:
let x = amt of 50% solution required
:
.24(16) + .50x = .35(x+16)
3.84 + .5x = .35x + 5.6
.5x - .35x = 5.6 - 3.84
.15x = 1.76
x = 1.76/.15
x = 11.73 liter of 50% solution required
: