Question 1043646
during an afternoon practice, two track team members took the same amount of time to run 18 miles and 12 miles, respectively. if one of the track team members ran 2 miles per hour faster than the other, what is the rate of each team member? 
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Faster runner DATA:
rate = x+2 mph ; distance = 18 miles ; time = d/r = 18/(x+2) hrs
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Slower runner DATA:
rate = x mph ; distance = 12 miles ; time = d/r = 12/x hrs
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Equation:
18/(x+2) = 12/x
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18x = 12x + 24
6x = 24
x = 4 mph (slower runner rate)
x+2 = 6 mph (faster runner rate)
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Cheers,
Stan H.
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