Question 1043591
{{{7^(2x+1) = 4^(x-2)}}}


{{{log((7^(2x+1)))=log((4^(x-2)))}}}


{{{(2x+1)log((7))=(x-2)*log((4))}}}


{{{2x*log((7))+log((7))=x*log((4))-log((4))}}}


{{{2x*log((7))-x*log((4))=-log((7))-log((4))}}}


{{{x(2*log((7))-log((4)))=-(log((7))+log((4)))}}}


{{{x=(-(log((7))+log((4))))/(2*log((7))-log((4)))}}}


{{{highlight(x=(log((7))+log((4)))/(log((4))-2*log((7))))}}}, or finish into whatever form you like.