Question 1043556
Express the following as a single logarithm[2

1.) (1/2)loga(x)-(3/2)loga(y)+(3/2)loga(z)
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= loga[x^(1/2)*z^(3/2)/y^(3/2)]
         

2.) logb(2x) + 3(logb(x)-logb(y))
= logb[2x*x^3/y]
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Cheers,
Stan H.
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