Question 1043558
<i>The product of two numbers is 48. The first number is negative,...</i>
...then both of the numbers are negative!!



{{{system(xy=48,y=4+2x)}}}


{{{x(2x+4)=48}}}
{{{2x^2+4x-48=0}}}
{{{x^2+2x-24=0}}}
{{{(x-4)(x+6)=0}}}
and we must take the NEGATIVE SOLUTION VALUE, according to the description.
{{{highlight(x=-6)}}}



We must also have a value from y according to the described system, listed at the top.
{{{y=4+2(-6)}}}
{{{y=4-12}}}
{{{highlight(y=-8)}}}-----which also is consistent with the other equation.