Question 1043547
Find the magnitude and direction angle (to the nearest tenth) for each vector. Give the measure of the direction angle as an angle in [0,360°]. 
(-12,5)
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Note: That point is in QII
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magnitude = sqrt[12^2+5^2] = 13
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direction = arctan(5/-12) = -22.62 or 180-22.62 = 157.38 degrees in QII
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Cheers,
Stan H.
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