Question 1043528
 solve log base of 125^1/5
{{{log(125,(1/5))}}} = y
exponent equiv
{{{125^y}}} = {{{1/5}}}
1/5 can be written as
{{{125^y}}} = {{{5^-1}}}
125 is five cubed
{{{5^(3y)}}} = {{{5^-1}}}
therefore 
3y = -1
y = {{{-1/3}}}