Question 1043478
.
{{{a^8 +b^8}}} = {{{(a^8 + 2a^4b^4 + b^8) - 2a^4b^4}}} = {{{(a^4+b^4)^2 - 2a^4b^4}}} = {{{(a^4+b^4)^2 -(sqrt(2)a^2b^2)^2)}}} = {{{(a^4+b^4+sqrt(2)a^2b^2)*(a^4+b^4-sqrt(2)a^2b^2)}}} 



Next time do not forget to put a question in your post.


In this case I was smart enough to guess your question.


(it is because there is only one question in math associated with {{{a^8 + b^8}}}: factor it).


But next time your post without a question can be disregarded and ignored (and remained unanswered).