Question 90755
Question:



Which of the ordered pairs 
	(3, 1), (7, 0), (–1, –2), (–25, 8)
are solutions for the equation x + 4y = 7?



Answer:


Given equation is  x + 4y = 7

To check whether the given ordered pair is a solution of the given equation, substitue x value and y value in the given equation.  If you get same vlue on both sides of the equal sign, then the ordered pair is a solution, otherwise not.


Take (3,1)

==> 3 + 4 * 1 = 7


==> 3 + 4 = 7


==> 7 = 7


That is (3,1) is a solution.


Take (7,0 )


==> 7 + 4* 0 = 7



==> 7 + 0 = 7


==> 7 = 7


That is (7,0) is a solution.



Take ( -1, -2 )


==> -1 + 4*-2 = 7



==> -1 -  8 = 7


==> -9 = 7,  which is not true



That is (-1,-2)  is not a solution.



Take (-25,8)



==> -25 + 4* 8 = 7


==> -25 + 32 = 7



==> 7 = 7, which is true.


That is (-25,8) is a solution 





That is  (3, 1), (7, 0),  (–25, 8) are the solutions of the given equation.



Hope you found the explanation useful.




Regards.


Praseena.