<PRE><B>Question 1043422</B>
Let vector A = &lt;-4,1,0&gt;, B= &lt;0,1,2&gt;, C = &lt;4,3,-1&gt;, and D = &lt;0,0,1&gt;.
We have to find the volume of the parallelipiped formed by the vectors B-A, C-A, and D-A.
The volume is given by the triple vector product [(C-A)x(B-A)]*(D-A).
B-A = &lt;4,0,2&gt;,
C-A = &lt;8,2,-1&gt;, and 
D-A = &lt;4,-1,1&gt;.

===&gt; [(C-A)x(B-A)]*(D-A) = {{{abs(matrix(3,3,4,-1,1,8,2,-1,4,-1,1)) = 8+4-8-(8+4-8) = 0}}}

===&gt; the parallelipiped is actually &quot;flat&quot;, and the points (-4,1,0), (0,1,2),(4,3,-1), and (0,0,1) are coplanar.</PRE>