Question 1043445
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Use the Pythagorean Theorem to find the lengths of the sides of the triangle.
a=x+3
b=x
c=15
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<pre>
{{{a^2 + b^2}}} = {{{c^2}}}  --->  {{{(x+3)^2 + x^2}}} = {{{15^2}}}  --->

{{{2x^2 + 6x + 9}}} = {{{225}}}  --->  {{{2x^2 + 6x - 216}}} = {{{0}}}  --->

{{{x^2 + 3x - 108}}} = {{{0}}}

Solve this quadratic equation. The roots are  x = 9  and/or  x = -12.

Reject the negative root. Hence, only x = 9 is the solution.

The legs are 9 and 12.

It is (3-4-5) Pythagorean triangle 9, 12, 15.
</pre>