Question 1043398
<pre>
                    RATE        TIME                DISTANCE
Camp to ghq           96         t+(11:46-07:32)     
ghq to Camp          113          t 
Total Consumed                                        5420.8
</pre>


Total distance that each travels must be the distance between the two locations.  Notice higher speed goes with lesser time.  Turn the time difference of time points into a time variable expression using t.


4 hours 46-32 minutes
4 hours 14 minutes
{{{4&7/30}}} hours


<pre>
                    RATE        TIME                DISTANCE
Camp to ghq           96         t+4&7/30           96(t+4&7/30)
ghq to Camp          113          t                 113*t
Total Consumed                                        5420.8
</pre>

{{{highlight(96(t+4&7/30)+113t=5420.8)}}}


Solve that for t.
The slower bus had been moving for 4 hours 14 minutes; and then the faster bus began its travel and did this for t hours.  The two buses pass each other t hours AFTER  11:46 - AM seemed to be implied throughout.