Question 1043391
Try synthetic division to break P one factor at a time.  You could try instead divisor x^2-16, but using synthetic division  with first x-4 and then x+4 divisors could be easier.  You still then need to handle the cubic result, whichever way you choose.


<pre>
4   |   1   -1   -20   20   64    -64
    |
    |       4    12    32   104   672
    ----------------------------------------
       1    3     8    52   168    608
</pre>

NO.  x-4 AND x+4  ARE NOT BOTH FACTORS OF P(x).