Question 1043143
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Sorry, but the description you give of your diagram is nonsense.  If triangle BAP is isosceles with AP = AB, then the line segment AR where R lies on the segment P must perforce be the perpendicular bisector of segment PB and the bisector of angle A.  Hence, if angle BAR = 60 degrees, then PAR must be 60 degrees also and therefore angle PAB must be 120 degrees, not 82 degrees as you stated.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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