Question 1043349
Probability one adult will dine out more than once a week is 188/1200
Probability  both selected will dine out more than once a week is (188/1200)(187/1199)=0.024
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Probability neither dines out is (1012/1200)*(1011/1199)=0.711
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Probability at least one should be the complement of 1-0711=0.289
This can be checked by  the ways one can occur
first and not second is (188/1200)(1012/1199)=0.132
not first but second is (1012/1200)(188/1199), same product just different order=0.132
both (since at least one) and that is 0.024
Those three add to 0.288, and rounding error is reason it isn't the complement exactly.
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As for the last part, unusual vs. usual is not a statistical question.  The answers are what they are.  If someone wishes to state whether it were surprising, it would be incumbent upon them to state what they thought and why.