Question 1043325
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if sin x=3/5,pi/2 < x < pi, then find the value of cos x,tan x,sec x and cot x
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<pre>
cos(x) = {{{-sqrt(1 - sin^2(x))}}} = {{{-sqrt(1-(3/5))}}} = {{{-sqrt(1 - 9/25)}}} = {{{-sqrt((25-9)/25)}}} = {{{-sqrt(16/25)}}} = {{{-4/5)}}}.

The sign "-" before the square root is because  pi/2 < x < pi  and cosine is negative in QII.

Now, knowing sin(x) and cos(x), you can easily calculate the remaining functions on your own.
</pre>

For similar problems, and to extend your knowledge, see the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Trigonometry-basics/Calculating-trigonometric-functions-of-angles.lesson>Calculating trigonometric functions of angles</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Trigonometry-basics/Selected-problems-from-the-archive-on-calculating-trig-functions-of-angles.lesson>Advanced problems on calculating trigonometric functions of angles</A>

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