<PRE><B>Question 1043288</B>
Solve each equation by either substitution or addition method.
x^2 + 4y^2 = 20 
x + 2y = 6
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x = 6-2y
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Substitute for &quot;x&quot; and solve for &quot;y&quot;::
(6-2y)^2 + 4y^2 = 20
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36 - 24y + 4y^2 + 4y^2 = 20
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8y^2 - 24y +16 = 0
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y^2 - 3y + 2 = 0
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(y-1)(y-2) = 0
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Solve for &quot;x&quot;
If y = 1, x = 6-2y = 4
If y = 2, x = 6-2y = 2
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Cheers,
Stan H.
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