Question 1043293
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Solve the equation for x, where x is restricted to the given interval.

y = -5 sin 8x, for x in (-pi/16, pi/16)
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The solution does exist if and only if  |y| <= 5, i.e.  -5 <= y <= 5.


If it is satisfied then the solution is unique and it is

    x = {{{(1/8)*arcsin(y/(-5))}}} = {{{(1/8)*arcsin(-y/5)}}} = {{{-(1/8)*arcsin(y/5)}}}, 

doesn't matter if "y" is positive or negative.
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