Question 1043253

The numerator of a fraction is 7 less than the denominator. If one and one third is added to it, the fraction obtained is 14/9. Find the original fraction.
<pre>Let numerator be N
Then denominator is N + 7
We then get: {{{N/(N + 7) + 1&1/3 = 14/9}}}
{{{N/(N + 7) + 4/3 = 14/9}}}
9N + 3(4)(N + 7) = 14(N + 7) ------ Multiplying by LCD, 9(N + 7)
Continue to solve for N, the numerator. You should get 2. 
Add 7 to the numerator to get 9. This makes the original fraction: {{{2/(2 + 7)}}}, or {{{highlight_green(2/9)}}}