Question 1043268
Hi there,
The graph of f(x) cuts the 
'y' axis when x = 0
f(x) = -2x^2 + 4x + 3
f(0) = -2(0)^2 + 4(0) + 3
f(0) = 3
Therefore the graph cuts 
the 'y' axis at (0,3)
Hope this helps :-)