Question 1043266
Hi there,
Substitute x = -1 into f(x)
f(x) = -3(x)^2 - 6x - 6
f(-1) = -3(-1)^2 - 6(-1) - 6
f(-1) = -3 + 6 - 6
f(-1) = -3  (y = -3)
So, yes point (-1, -3)lies
on the graph of f(x).
Hope this helps :-)