Question 1043212
If 4x-y=2/3, what is the value of {{{81^(3x)/27^y}}}
we can rewrite this to
{{{(3^4)^(3x)/(3^3)^y}}}
which is
{{{3^(12x)/3^(3y)}}} = {{{3^(12x-3y)}}} = {{{3^(3(4x-y))}}} = {{{27^((4x-y))}}}
:
Note that the equation is 4x-y = 2/3, therefore 
we can replace 4x-y with 2/3 so be now have
{{{27^((2/3))}}} = 9