Question 1043213
((3+i)/(2-i))(a+bi)=1  In the equation above, a and b are constants. If i=sqrt(-1). what is the value of a?
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(6-3i+2i+1)(a+bi) = 1
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(7-i)(a+bi) = 1 + 0i
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7a+b + (7b-a)i = 1 + 0i
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7a + b = 1
-a + 7b = 0
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Modify for elimination::
7a + b = 1
-7a + 49b = 0
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Add and solve for "b"::
50b = 1
b = 1/50
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Solve for "a":
7a + b = 1
7a = (49/50)
a = 7/50
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Cheers,
Stan H.
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