Question 1043206
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Simplify the expression: (n!)²-(n-1)!n!/(n-1)!n!
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Let us start with the numerator.

{{{(n!)^2 - (n-1)!*n!}}} = {{{n!*(n-1)!*(n - (n-1))}}} = n!*(n-1)!.


Did you noticed that it is exactly the denominator?

The answer is: 1.
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