Question 1043209
The population mean annual salary for environmental compliance specialists is about $62,000. A random sample of 35 specialists is drawn from this population. What is the probability that the mean salary of the sample is less than $60,000. Assume the standard deviation is $5,600. 
----------------
z(60,000) = (60,000-62000)/[5600/sqrt(35)] = -2.1129
----
P(x-bar < 60,000) = P(z < -2.1129) = normalcdf(-100,-2.1129) = 0.0173
==========
Cheers,
Stan H.
---------------