Question 1043194

How do I Complete the Square?
{{{3x^2 + 7x=4}}}

Thank you so much :)
<pre>{{{3x^2 + 7x = 4}}}
{{{3x^2/3 + 7x/3 = 4/3}}} ------- Dividing each expression by 3 to make the leading coefficient 1
{{{x^2 + (7/3)x = 4/3}}}
{{{x^2 + (7/3)x + ((1/2) * (7/3))^2 = 4/3 + ((1/2) * (7/3))^2}}} ------ Taking {{{1/2}}} of "b," squaring it, and then adding it to both sides
{{{x^2 + (7/3)x + (7/6)^2 = 4/3 + (7/6)^2}}} 
{{{(x + 7/6)^2 = 4/3 + 49/36}}}
{{{(x + 7/6)^2 = 48/36 + 49/36}}}
{{{(x + 7/6)^2 = 97/36}}}
{{{sqrt((x + 7/6)^2) = ""+- sqrt(97/36)}}} ------ Taking the square root of both sides
{{{x + 7/6 = ""+- sqrt(97)/6}}}
{{{highlight_green(matrix(1,7, highlight(x = sqrt(97)/6 - 7/6), "=======>", highlight(x = (sqrt(97) - 7)/6), or, highlight(x = (- sqrt(97))/6 - 7/6), "======>", highlight((- sqrt(97) - 7)/6)))}}}