Question 1043203
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If x+y=12 and x-y=4, what is the value of {{{(x^2-y^2)/2x}}}
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x + y = 12   (1)
x - y =  4   (2).

Add (1)  and (2). You will get 2x = 16, hence, x = 8.
Then y = 4.


From this point, complete it on your own.
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