Question 1043150
First thing is to try to find what you are actually given, and it seems to be this:


{{{(9^y*3^2*(3^(-y))^(-1)-27^y)/3^(3x)*2^3=1/27}}}



No, that's not it.



Must be this:


{{{(9^y*3^2*(3^(-y))^(-1)-27^y)/(3^(3x)*2^3)=1/27}}}