Question 1043117
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A rectangle has an area of 126 cm2 and a perimeter of 50 cm. What are its dimensions? 
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<pre>
L + W = {{{50/2}}},
LW = 126.

or

L + W = 25,   (1)
LW = 126      (2)

Express L = 25-W from (1) and substitute it into (2). You will get

(25-W)*W = 126,  or

{{{W^2 - 25W + 126}}} = {{{0}}}.

Solve this quadratic equation for W. Factor the left side

(W-7)*(W-18) = 0

<U>Answer</U>.  The width is 7 cm. The length is 18 cm.
</pre>

For many other similar solved problems see the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Surface-area/Problems-on-the-area-and-the-perimeter-of-a-rectangle.lesson>Problems on the area and the perimeter of a rectangle</A>

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