Question 1043108
<pre><b>

{{{system(x+y=s,y-x=expr(1/m)*y)}}}

Solve the first equation of the system for y

{{{x+y}}}{{{""=""}}}{{{s)}}}

{{{y}}}{{{""=""}}}{{{s-x)}}}

Now substitute (s-x) for y in the second equation of the system.

y-x=expr(1/m)*y

{{{(s-x)-x=expr(1/m)*(s-x)}}}

Multiply through by m

{{{m(s-x)-mx=s-x}}}

{{{ms-mx-mx=s-x}}}

{{{ms-2mx=s-x}}}

{{{x-2mx=s-ms}}}

{{{x(1-2m)=s-ms)}}}

{{{x=(s-ms)/(1-2m)}}}

{{{y}}}{{{""=""}}}{{{s-x)}}}

{{{y}}}{{{""=""}}}{{{s-(s-ms))/(1-2m))}}}

{{{y}}}{{{""=""}}}{{{(s(1-2m))/(1-2m)-(s-ms)/(1-2m)}}}

{{{y}}}{{{""=""}}}{{{(s-2ms)/(1-2m)-(s-ms)/(1-2m)}}}

{{{y}}}{{{""=""}}}{{{((s-2ms)-(s-ms))/(1-2m)}}}

{{{y}}}{{{""=""}}}{{{(s-2ms-s+ms)/(1-2m)}}}

{{{y}}}{{{""=""}}}{{{(-ms)/(1-2m)}}}

Multiply top and bottom by -1

{{{y}}}{{{""=""}}}{{{(ms)/(-1+2m)}}}

{{{y}}}{{{""=""}}}{{{(ms)/(2m-1)}}}


Edwin</pre></b>