<PRE><B>Question 1043016</B>
The length of a rectangle is 
3 m
 more than twice the width and the area of the rectangle is 
35 m2
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L = 2W + 3
L*W = 35
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sub for L
W*(2W+3) = 35
2W^2 + 3W - 35 = 0
*[invoke solve_quadratic_equation 2,3,-35]
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W = 3.5 meters
L = 10</PRE>